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"What is the ratio of the solubilities of "N_(2)"and" O_(2)"in"H_(2)O "at" 373 "K, given that "K_(H)(N_(2))=12.6xx10^(4)" atm and "K_(H)(O_(2)) =7.01xx10^(4)? "Assume that" p(N_(2))=0.80 "atm and" p(O_(2))=0.20 atm

Answer»

Solution :The ratio of the solubilities of the gases can be EXPRESSED in terms of their mole fractions. Accrding toHenry's low,
`x_((N_(2)))=(p_((N_2)))/(K_(H(N_2)))=((0.80 ATM))/((12.6xx10^(4)atm)`
`x_((O_(2)))=(p_((O_2)))/(K_(H(O_2)))=((0.20 atm))/((7.01xx10^(4)atm)`
`x_(N_2)/x_(O_2)=((0.80atm))/((12.6xx10^(4)atm))XX((7.01xx10^(4)))/((0.20 atm))=2.22`


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