1.

What is the reaction quotient , Q for the cell Ni_((s)) | Ni^(2+) (0.190 M) || Cl^(-) (0.40 M) | Pt_((s)) Cl_(2(g)) (1.0 atm)

Answer»

`3.1 xx 10^(-1) `
` 1.3 xx 10^(-1) `
` 8.0 xx 10^(-2)`
`3.0 XX 10^(-2)`

SOLUTION :`NI + Cl_2 to Ni^(+2) + 2Cl^(Ɵ) , Q = ((Ni^(+2))(CL^(Ɵ))^(2))/((PCl_2)^(1)) =(0.190 xx (0.4)^2)/(1) = 0.0304 = 3.04 xx 10^(-2)`


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