What is the relation between noise temperature introduced by beam TB and the antenna temperature TA when the solid angle obtained by the noise source is greater than antenna solid angle?(a) TA= TB(b) TA > TB(c) TA < TB(d) TA « TBI had been asked this question in class test.My question comes from Antenna Noise Temperature in portion Antenna Parameters – II of Antennas

What is the relation between noise temperature introduced by beam TB a

1.	What is the relation between noise temperature introduced by beam TB and the antenna temperature TA when the solid angle obtained by the noise source is greater than antenna solid angle?(a) TA= TB(b) TA > TB(c) TA < TB(d) TA « TBI had been asked this question in class test.My question comes from Antenna Noise Temperature in portion Antenna Parameters – II of Antennas
Answer» Correct option is (a) TA= TB The explanation is: When the solid ANGLE obtained by the noise source ΩB is GREATER than antenna solid angle ΩA, then RELATION between noise temperature introduced by BEAM TB and the antenna temperatureTAis given by TA= TB (If Lossless antenna). For radio astronomy, ΩB<ΩA and TA≠ TB; ΔTA=\(\frac{\Omega_B}{\Omega_A}T_B\)

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