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What is the relation between voltage and current in AC circuit containing only capacitance? |
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Answer» Current (I) is leading the voltage by 90°. I = V/XC amps. XC = 1/2πfC ohms. P = I * V * cosϕ watts. (Where cosϕ is 90 because current is leading the voltage by 90°. So cosϕ 90° = 0) ∴ P = I * V * 0 = 0 watts. |
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