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| 1. |
What is the relationship between cp and cv |
| Answer» ∆H=∆U + nR∆T.......(1) (∆H= nCp∆T) (∆U= nCv∆T)For one mole of a gas,n=1On putting values of ∆H and ∆ U in eq. 1Cp∆T= Cv∆T+ R∆T(Cp-Cv)∆T=R∆T=> Cp-Cv=R | |