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What is the relationship between Gibbs free energy of the cell reaction is a galvanic cell and the emf of the cell ? When will the maximum work be obtained from a galvanic cell ? |
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Answer» Solution :* In general `Delta_(r)G^(@)=nFE` Where, `Delta_(r)G^(@)=`Gibbs energy of the cell reaction. n=Number of moles of electrons TRANSFERRED in the redox reaction taking place in a cell. F=Faraday CONSTANT E=Cell emf * Using standard conditions, the reaction is `Delta_(r)G^(@)=nFE^(@)` Where, `Delta_(r)G^(@)=`standard Gibbs energy of the cell reaction, * `E^(@)=`Standard cel emf If we want to obtain maximum work from a galvanic cell than charge has to be PASSED reversibly. |
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