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What is the relative speed improvement over Cohen-Sutherland algorithm for 2-D lines?(a) 40%(b) 50%(c) 70%(d) 36%I had been asked this question during an online exam.My question comes from Liang-Barsky Line Clipping topic in chapter 2D Transformation and Viewing of Computer Graphics

Answer» CORRECT choice is (d) 36%

The best I can EXPLAIN: The relative SPEED improvement over Sutherland-Cohen algorithm are: – 36% for 2D lines, 40% for 3D lines, 70% for 4D lines.


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