1.

What is the remainder when x2018 + 2018 is divided by x – 1.

Answer»

x2108 + 2018 is divided by x – 1 

Let g(x) = x – 1 = 0 

x = 1 

p(x) = x2018 + 2018 

p(1)= 12018 + 2018 

= 1 + 2018 = 2019



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