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What is the self inductance of a coil in which an induced emf of 2V is set up, when the current is changing at the rate of ` 4 A s ^( - 1 ) `A. 0.5 mHB. 0.05 HC. 2 HD. 0.5 H

Answer» Correct Answer - D
Induced emf ` e = ( Ldi) /( dt )`, hence ` e = 2V, (di )/( dt ) = 4 As ^( -1 ) `
` rArr 2 = L xx 4 `
` L = ( 2 )/( 4 ) = 0. 5 H `


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