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What is the shortest wavelength present in the Paschen series of spectral lines?A. 720 nmB. 790 nmC. 800 nmD. 820 nm

Answer» Correct Answer - D
The wavelength for Paschen series,
`(1)/(lambda)=R[(1)/(3^2)-(1)/(n^2)]`
For shortest wavelength `n=prop`
`therefore (1)/(lambda)=R[(1)/(9)-(1)/(prop^2)]=(R)/(9)rArrlambda=(9)/(R)=(9)/(1.097xx10^7)`
`=8.20xx10^-7m=820nm`.


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