What is the shortest wavelength present in the Paschen series of spect

1.	What is the shortest wavelength present in the Paschen series of spectral lines?
Answer» Rydberg’s formula is given as \(\frac{hc}{\lambda} = 21.76 \times 10^{-19}(\frac{1}{n_1^2}-\frac{1}{n_2^2})\) h = 6.6 x 10^-34 is the plank's constant. c = 3 x 10⁸ is speed of life. The shortest wavelength present in the Paschen series of the spectral lines is given for values n₁ = 3 and n₂ = \(\infty\) From the above values, \(\lambda = 819nm\)

What is the shortest wavelength present in the Paschen series of spectral lines?

Answer»

Rydberg’s formula is given as

\(\frac{hc}{\lambda} = 21.76 \times 10^{-19}(\frac{1}{n_1^2}-\frac{1}{n_2^2})\)

h = 6.6 x 10^-34 is the plank's constant.

c = 3 x 10⁸ is speed of life.

The shortest wavelength present in the Paschen series of the spectral lines is given for values n₁ = 3 and n₂ = \(\infty\)

From the above values,

\(\lambda = 819nm\)