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What is the smallest electric force between two charges placed at a distance of `1.0m`? |
Answer» `F_e=1/(4piepsilon_0).(q_1q_2)/r^2` For `F_e` to be minimum `q_1q_2` should be minimum. We know that `(q_1)_(min)=(q_(2))_(min)=e=1.6xx10^(-19) C ` `(F_(e))_(min)=((9.0xx10^9)(1.6xx10^-19)(1.6xx10^-19))/((1.0)^2)` `=2.304xx10^-28N` |
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