

InterviewSolution
Saved Bookmarks
1. |
What is the smallest natural number n such that n! is divisible by 990 |
Answer» Factors of `990 = 11**3^2**2**5` Smallest number `n` such that `n!` is divisible by `11` is `11`. `11!` is also divisible by `9,2 and 5`. So, `11!` will have all these factors `11,9,5 and 2`. So, smallest number that is divisible by `990` is `11!`. |
|