1.

What is the solubilityproduct (K_(sp))of calcuim phosphate in pure water ? [S=molar solubility]

Answer»

`108 X^(2) `
` 36 x^(3) `
` 36 x^(5)`
` 108 x ^(5) `

Solution :`Ca_3 (PO_4)_2 hArr 3Ca^(+2)+2PO_4^(3-) `
`"" 3X "" 2X `
` Ksp= (3x) ^(3)(2x)^(2) =108x^(5)`


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