What is the solution to the equation 5/(3b3 -2b2 - 5) = 2/(b3 - 2)? b = -4 and b = 0,b = -4,b = 0 and b = 4,b = 4

What is the solution to the equation 5/(3b3 -2b2 - 5) = 2/(b3 - 2)? b

1.	What is the solution to the equation 5/(3b3 -2b2 - 5) = 2/(b3 - 2)? b = -4 and b = 0,b = -4,b = 0 and b = 4,b = 4
Answer» What is the solution to the equation 5/(3b³-2b²- 5) = 2/(b³- 2)? Solution: