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What is the standard value for the radius of curvature rc to be equal to the radius of earth re?(a) rc=4re(b) rc=\(\frac{4r_e}{3}\)(c) rc=re(d) rc=\(\frac{1}{4}\) reI had been asked this question during an interview.The origin of the question is Space Wave Propagation topic in section Space Wave Propagation of Antennas

Answer»

The correct answer is (a) rc=4re

For explanation: The RADIUS of curvature is FOUR times the radius of earth. rc=4re

The EFFECTIVE radius factor of earth is 4/3 times actual radius of earth.



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