1.

What is the strength in grams/litre of a solution of H_(2)SO_(4) ,12 c c of which neutralises 15 c c of N/10 NaOH solution ?

Answer»

Solution :m.e of NAOH solution = `1/10 xx15 = 1.5""….(Eqn.1)`
m.e of 12 c c of `H_(2)SO_(4)=1.5""…(Eqn.2)`
` :. " normality of" H_(2)SO_(4)=(1.5)/2 ""…(Eqn.1)`
STRENGTH on grams/litre = normality `xx` eq.wt…(Eqn.5)
` = (1.5)/12 xx 49` grams.litre
` = 6.12` grams/litre
`{ " eq. wt of " H_(2)SO_(4)=("mol.wt")/("basicity") = 98/2 = 49}`


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