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What is the sum of all natural numbers between 1 and 150 (both included) which are multiples of 3?1). 38252). 42353). 37354). 4415 |
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Answer» The numbers are 3, 6, 9…., 150 Nth TERM of an AP = a + (n - 1)d 3 + (n - 1)3 = 150 ⇒ n = 50 Sum of n terms of an AP = n/2(2a + (n - 1)d) Where a is first term, n is NUMBER of terms and d is common difference a = 3, n = 50 and d = 3 Sum = 50/2 × (6 + 49 × 3) = 3825 |
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