What is the sum of the perimeters of all the squares of sides 14 cm ob

1.	What is the sum of the perimeters of all the squares of sides 14 cm obtained from the rectangular sheet of dimension 3.5 m × 2.8 m?1. 280 m2. 240 m3. 160 m4. 320 m
Answer» Correct Answer - Option 1 : 280 m Given: The side of the square is 14 cm and the dimension of the rectangular sheet is 3.5 m × 2.8 m. Formula Used: Area of square = Side × Side Area of rectangle = length × breadth The perimeter of square = 4 × side Calculation: The number of squares obtained from the rectangular sheet = (3.5 m × 2.8 m)/ (14 cm × 14 cm) The number of square obtained = (350 cm × 280 cm)/(14 cm × 14 cm) = 500 Now, perimeter of one square = 4 × 14 = 56 cm Perimeter of all the square obtained = 500 × 56 = 28000 cm = 280 m ∴ The perimeter of all the squares is 280 m.

What is the sum of the perimeters of all the squares of sides 14 cm obtained from the rectangular sheet of dimension 3.5 m × 2.8 m?1. 280 m2. 240 m3. 160 m4. 320 m

Answer» Correct Answer - Option 1 : 280 m

Given:

The side of the square is 14 cm and the dimension of the rectangular sheet is 3.5 m × 2.8 m.

Formula Used:

Area of square = Side × Side

Area of rectangle = length × breadth

The perimeter of square = 4 × side

Calculation:

The number of squares obtained from the rectangular sheet = (3.5 m × 2.8 m)/ (14 cm × 14 cm)

The number of square obtained = (350 cm × 280 cm)/(14 cm × 14 cm) = 500

Now, perimeter of one square = 4 × 14 = 56 cm

Perimeter of all the square obtained = 500 × 56 = 28000 cm = 280 m

∴ The perimeter of all the squares is 280 m.

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