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What is the t.s.a of hollow cylinder |
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Answer» let r1 be inner radius and r2 be outer radius inner csa = 2 pie r1 houter csa = 2 pie r2 hsurface area of circle at ends = pie r2^2 - pie r1^ 2 tsa = 2 pie h ( r2 + r1 ) + pie ( r2^2 - r1^ 2 ) 2πr(h+r) |
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