1.

What is the t.s.a of hollow cylinder

Answer» let r1 be inner radius and r2 be outer radius inner csa = 2 pie r1 houter csa = 2 pie r2 hsurface area of circle at ends = pie r2^2 - pie r1^ 2 tsa = 2 pie h ( r2 + r1 ) + pie ( r2^2 - r1^ 2 )
2πr(h+r)


Discussion

No Comment Found