What is the temperature of the triple - point of water on an absolute scale whose unit interval size is equal to that of the Fahrenheit scale ?

What is the temperature of the triple - point of water on an absolute

1.	What is the temperature of the triple - point of water on an absolute scale whose unit interval size is equal to that of the Fahrenheit scale ?
Answer» <html><body><p></p>Solution :Rotation between Fahrenheit and kelvin scale. <br/> `(T_(F)-32)/(180)=(T_(K)-273)/(<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>)`. . . (1)<br/> <a href="https://interviewquestions.tuteehub.com/tag/fo-457881" style="font-weight:bold;" target="_blank" title="Click to know more about FO">FO</a> different <a href="https://interviewquestions.tuteehub.com/tag/temperature-11887" style="font-weight:bold;" target="_blank" title="Click to know more about TEMPERATURE">TEMPERATURE</a>, <br/> `(T_(F)^(.)-32)/(180)=(T_(K)^(.)-273)/(100)`. . . (<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) <br/> By subtracting equating (2) from equation (1) <br/> `(T_(F)^(.)-T_(F))/(180)=(T_(K)^(.)-T_(K))=(T_(K)^(.)-T_(K))/(100)` <br/> `:.T_(F)^(.)-T_(F)=(180)/(100)(T_(K)^(.)-T_(K))` <br/> But `T_(K)^(.)-T_(K)=1K` <br/> `:.T_(F)^(.)-T_(F)=(180)/(100)` <br/> Now new temperature at triple point is `273.16K`, <br/> Tmeprature `=273.16xx(180)/(100)` <br/> `=491.688" "^(@)F~~491.69^(@)F`</body></html>