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What is the time period of rotation of the earth around its axis so that the objects at the equator becomes weightless? (`g=9.8 m//s^2`, radius of the earth `=6400km`) |
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Answer» When the earth is is rotating the apparent weight of a body at the equator is given by `W_(app)=mg-mRomega^(2)` If bodies are weightless at the equator `0=mg-mRomega^(2) rArr g=Romega^(2)` `rArr omega=sqrt(g/R)` Time periode, `T=(2pi)/(omega)=2pipsqrt(R/g)` `T=2pisqrt((6.4xx10^(6))/9.8)=5078 s =84` minute `38 s` |
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