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What is the total number of electrons present in 1.6 g of methane?

Answer»


Solution :The molecular formula of methane is `CH_4`. Since, one atom of carbon CONTAINS 6 electrons and one atom of hydrogen contains one electron, one molecule of methane will CONTAIN 10 electrons.
The gram molecular MASS of methane `=12.01 + (4 XX 1.008) = 16.042 G`
This mass will contain `6.022 xx 10^23` molecules.
Hence, the total number of electrons present in 1.6 g of methane = `6.0 xx 10^(22) xx 10 = 6.0 = 10^(22)`


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