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What is the total number of electrons present in 1.6 g of methane? |
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Answer» The gram molecular MASS of methane `=12.01 + (4 XX 1.008) = 16.042 G` This mass will contain `6.022 xx 10^23` molecules. Hence, the total number of electrons present in 1.6 g of methane = `6.0 xx 10^(22) xx 10 = 6.0 = 10^(22)` |
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