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What is the total number of orbitals associated with the principal quantum number n = 3? |
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Answer» Solution :For n = 3, L = 0, 1, 2, i.e., there are three subshells DESIGNATED as 3s, 3p and 3d For 3s subshell, l = 0, `:.` m = 0 (i.e., one orbital), For 3p subshell, l = 1, `:.m = -1, 0 + 1` (i.e., 3 ORBITALS ) For 3d subshell l = 2, `m = -2, -1, 0 + 1, + 2` (i.e., 5 orbitals) `:.` TOTAL no. of orbitals PRESENT in the shell with n = 3 will be 1 + 3 + 5 = 9 Alternatively, no of orbitals presents in nth shell `= n^(2):.` No. of orbitals in the 3rd shell (n = 3) `= 3^(2) = 9` |
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