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What is the total number of orbitals present in the shell with the principal quantum number, n = 3 |
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Answer» Solution :For n = 3, the possible VALUES of l are 0,1 and 2. Thus, there is one 3S orbital (n = 3, l = 0 and `m_l` = 0), there are three p orbitals (n = 3, l = 1 and ml = -1, 0, 1) there are five 3D orbitals (n = 3, l = 2, ml = -2, -1, 0, 1, 2). Therefore, the total number of orbitals is 1+3+5 = 9. |
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