1.

What is the total volume of atom present in body centered unit cell having edge length 69.3 pm ?

Answer»

`2.26 xx 10^(4) "pm"^(3)`
`2.26 xx 10^5 "pm"^3`
`1.13 xx 10^6 "pm"^3`
`1.13 xx 10^(5) "pm"^3`

Solution :For bcc lattice `R = (sqrt(3))/4 a`
`r = (sqrt3)/(4) xx69.3` = 30 pm
`THEREFORE` Volume of total atoms of CUBE ` 8/3 pi r^3`
`= 8/3 xx 22/7 (30)^(3)`
`= 2.26 xx 10^(5) "pm"^3`.


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