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What is the value of 1n2 × 2n1? |
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Answer» 1n2 = \(\frac{n_2}{n_1}\) and 2n1 = \(\frac{n_1}{n_2}\) ⇒ 1n2 x 2n1 = \(\frac{n_2}{n_1}\) x \(\frac{n_1}{n_2}\) = 1. Hence the answer is 1. |
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