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What is the value of. (a) `0^@ F` in Celsius scale ? (b) (0 K) on fahrenheit scale ? |
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Answer» Correct Answer - A::B::C::D (a) `(T_C - 0)/(100) = (T_F - 32)/(180)` Putting `T_F = 0`, we get `T_C = -17.8^@ C` (b) `(T_C - 0)/(100) = (T_F - 32)/(180)` or `(T_K -273)/(100) = (T_K - 32)/(180)` putting `T_K = 0`, we get `T_F = -459.67^@ F`. |
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