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What is the value of acceleration due to gravity on the surface of earth if the entire earth was made of gold ? (Radius of earth = 6400 km , Density of gold = 19.3 xx 10^(3) kg//m^3 and G = 6.67 xx 10^(-11) MKS) |
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Answer» Solution :`IMPLIES` Here, `R_e = 6,400 km . = 64 xx 10^(5) m` `rho = 19.3 xx 10^(3) kg./m^3` `G = 6.67 xx 10^(-11) Nm^(2)//kg^(2)` Mass of EARTH Me = `4/3piRe_^3 rho` `implies g = (GM_e)/(R_e)` `implies g = (G)/(R_e^2) (4/3piRe^2rho)=4/3 piGrhoRe` `:. g = (4 xx 3.14 xx 6.67 xx 10^(-11) xx 19.3 xx 10^(3) xx 64 xx 10^5)/3` `:. g = (12.56 xx 6.6xx 19.3 xx 64 xx 10^(-3))/3` ` :. g = 34.49 m//s^2` |
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