1.

What is the value of decay constant of a compound having half-life time T_(1//2) = 2.95 days

Answer»

`2.7 xx 10^(-5) s^(-1)`
`2.7 xx 10^(6) s^(-1)`
`2.7 xx 10^(-6) s^(-1)`
`3 xx 10^(5) s^(-1)`

Solution :`t_(1//2) = 2.95`days
`= 2.95 xx 24 xx 60 xx 60X = 254880`
`lamda = (0.693)/(t_(1//2)) = (0.693)/(254880) = 2.7 xx 10^(-6) s^(-1)`


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