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InterviewSolution
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What is the value of `k_(c)` for the reaction at 1473 K `I_(2)(g) hArr 2I(g)` when one mode of iodic gas is introduced into an evacuated one litre flask so that only 5% of it gets dissociated ? |
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Answer» `{:(,I_(2)(g) ,hArr, 2I(g)),("Initial no. of moles"// "litre", 1 ,, 0),("No. of moles"// "litre at equilibrium",1-0.05,, 0.05 xx 2),(,=0.95,,=0.1):}` Applying Law of chemical equilibrium `K_(c) =[[(g)]^(2)]/[[I_(2)(g)]] =((0.1 "mol "L^(-1))(0.1 "mol " L^(-1)))/((0.95 "mol "L^(-1)))` `=0.0105 =1.05 xx 10^(-2) "mol "L` |
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