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What is the value of kb in nominal bearing strength for a bolt of 20mm diameter of grade 4.6?(a) 0.5(b) 1(c) 0.97(d) 2I got this question in a national level competition.My doubt is from Bolted Connections topic in division Bolted Connections of Design of Steel Structures

Answer»

The CORRECT option is (a) 0.5

To explain I would say: DIAMETER of bolt = 20MM, diameter of hole = 20+2 =22mm

e=1.5×22=33mm, p=2.5×20=50mm

e/3d0 = 33/(3×22) = 0.5, p/3d0-0.25 = 50/(3×22) -0.25=0.5, fub /fb= 400/410=0.975

kb= MINIMUM of (e/3d0 , p/3d0-0.25, fub /fb, 1) = 0.5.



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