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What is the value of \(\lim\limits_{x \rightarrow \infty}\frac{x^2-9}{x^2–3x+2}\)?(a) 1(b) 2(c) 0(d) Limit does not existI have been asked this question in an online quiz.Enquiry is from Limits in division Limits and Derivatives of Mathematics – Class 11

Answer»

Correct CHOICE is (a) 1

Explanation: Since it is of the form \(\FRAC{\infty}{\infty}\), we use L’Hospital’s rule and differentiate the numerator and denominator

L = \(\lim\limits_{X \rightarrow \infty}\frac{x^2-9}{x^2–3x+2}\)

On differentiating once, we get \(\lim\limits_{x \rightarrow \infty}\frac{2x}{2x}\)

Which is EQUAL to, \(\lim\limits_{x \rightarrow \infty}\) ⁡1 = 1.



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