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| 1. |
What is the value of m in ( i+mj+k)cap to be unit vector? |
| Answer» For unit vector, we have{tex}| \\hat { \\mathbf { i } } + m \\hat { \\mathbf { j } } + \\hat { \\mathbf { k } } | = \\sqrt { 1 + m ^ { 2 } + 1 } = 1{/tex}m2\xa0+ 2 = 1{tex}m ^ { 2 } = - 1 \\Rightarrow m = \\sqrt { - 1 }{/tex}Hence, m is imaginary number. | |