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What is the value of the limit f(x) = \(\frac{sin^2x+\sqrt 2 sin x}{x^2-4x}\) if x approaches 0?(a) \(\frac{1}{\sqrt 2}\)(b) \(\frac{-1}{\sqrt 2}\)(c) \(\frac{-1}{2\sqrt 2}\)(d) \(\frac{1}{2\sqrt 2}\)I have been asked this question in an interview for internship.This is a very interesting question from Limits of Trigonometric Functions topic in chapter Limits and Derivatives of Mathematics – Class 11 |
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Answer» Correct answer is (c) \(\frac{-1}{2\sqrt 2}\) |
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