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What is the vapour pressure of the solution prepared by dissolving 0.5 gram substance (Molecular weight 65) in 100 mL C Cl_(4) ? The vapour pressure of C Cl_(4) is 143 mm. density of C C_(4) is 1.58. |
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Answer» 143.99 mm `w_(A)=` volume `xx` DENSITY `=100xx1.58=158` gram `C Cl_(4)` `M_(B)=65` gram/volume `M_(A)=154` gram/volume `(p^(@)-p)/(p^(@))=(w_(B).M_(A))/(w_(A).M_(B))=(0.5xx154)/(158xx65)` `therefore p=141.97` gram. |
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