1.

What is the voltage across the inductor when the source voltage is 200V and the Q factor is 10?(a) 100V(b) 20V(c) 2000V(d) 0V

Answer» Right option is (c) 2000V

The explanation is: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.

Q=VL/VS   where VL is inductive voltage and VS is source voltage.                                                                                                                                            10=VL/200   =>  VL = 2000 V.


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