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What is the voltage across the inductor when the source voltage is 200V and the Q factor is 10?(a) 100V(b) 20V(c) 2000V(d) 0V |
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Answer» Right option is (c) 2000V The explanation is: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage. Q=VL/VS where VL is inductive voltage and VS is source voltage. 10=VL/200 => VL = 2000 V. |
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