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What is the volume occupied by one `C Cl_(4)` molecule at `20^(@)C`? Density of `C Cl_(4)` is `1.6//cc` at `20^(@)C`

Answer» `C Cl_(4)` molecule is liquid.
`Mw` of `C Cl_(4) = 12 + 4 xx 35.5 = 154 g`
1 molecule of `C Cl_(4) = (154)/(6.023 xx 10^(23)) = 25.56 xx 10^(-23) g`
Volume of one molecule `= ("Mass")/("density")`
`= (25.56 xx 10^(-23))/(1.6)`
`= 1.598 xx 10^(-22) mL or cm^(3)`


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