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What is the volume occupied by one `C Cl_(4)` molecule at `20^(@)C`? Density of `C Cl_(4)` is `1.6//cc` at `20^(@)C` |
Answer» `C Cl_(4)` molecule is liquid. `Mw` of `C Cl_(4) = 12 + 4 xx 35.5 = 154 g` 1 molecule of `C Cl_(4) = (154)/(6.023 xx 10^(23)) = 25.56 xx 10^(-23) g` Volume of one molecule `= ("Mass")/("density")` `= (25.56 xx 10^(-23))/(1.6)` `= 1.598 xx 10^(-22) mL or cm^(3)` |
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