1.

What is the volume of '20 volume H_(2)O_(2)' required to get 5000 cm^(3) of oxygen at S.T.P ?

Answer»

`250cm^(3)`
`50cm^(3)`
`100cm^(3)`
`125cm^(3)`

Solution :20 VOLUME `H_(2)O_(2)`
`because` 20cc oxygen OBTAINED form=1 cc `H_(2)O_(2)`
`THEREFORE `1cc oxygen obtained from
`=(1)/(20)` cc `H_(2)O_(2)`
`therefore `5000 cc oxygen obtained from
`=(5000)/(20)` cc `H_(2)O_(2)=250` cc `H_(2)O_(2)`.


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