1.

What is the volume of CO_2liberated (in litres)at 1 atmosphere and 0^@Cwhen 10 g of 100% pure calcium carbonate is treated with excess dilute sulphuric acid ? (Atomic mass Ca = 40, C = 12, O = 16)

Answer»

0.224
2.24
22.4
224

Solution :`underset("1MOL(100 g)")(CaCO_3) + H_2SO_4 to CaSO_4+ H_2O+ underset("1mol (22.4L) )(CO_2)`
100 g of `CaCO_3` liberate `CO_2 = 22.4 L`
10 g of `CaCO_3` will liberate `CO_2 = (22.4)/(100) XX 10 = 2.24 L `


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