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What is the volume of oxygen liberated at S.T.P When 3.4g of H_(2)O_(2) is heated? |
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Answer» Solution :`2H_(2)O_(2)to2H_(2)O+O_(2)` `2"moles" ""1 "MOLE"` `2xx34 = 68gm`22.4lt as S.T.P From the blanced equation , we can SAY that 68g of `H_(2)O_(2)` on complete decomposition LIBERATES `(22.4)/(68)xx3.4 =1.12 LIT`. |
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