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What is the volume pecent of a solution prepared by dissolving 15 `cm^(3)` of methanol in `100 cm^(3)` of ethanol?

Answer» Volume of methanol = `15 cm^(3)`
Volume of ethanol = `100 cm^(3)`
`therefore` volume of the solution `= (15+100)=115 cm^(3)`
`therefore` volume per cent of solution = `(15)/(115)xx100=13.04%`


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