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What is the wavelength for the electron accelerated by 1.0xx10^(4) volts? |
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Answer» Solution :Step I.Calculation of the velocity of elctron ENERGY (kinetic energy)of eectron`=1.0xx10^(4)`volts. `=1.0xx10^(4)xx1.6xx10^(-19)J=1.6xx10^(-15)J` `=1.6xx10^(-15)kgm^(2)s^(-2)` or`(1)//(2) mv^(2)=1.6xx10^(-15)kgm^(2)s^(-2)` or`v=9((2xx1.6xx10^(-15)kgm^(2)s^(-2))/(9.1xx10^(-31)kg))^(1//2)=5.93xx10^(7)MS^(-1)` Step II. Calculation of WAVELENGTH of the electron According to de Broglie equation, `gamma=h/(mv),gamma=((6..626xx10^(-34)kgm^(2)s^(-1)))/((9.1xx10^(-31)kg)xx(5.93xx10^(7)ms^(-1)))=1.22xx10^(-11)m` |
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