1.

What is the wavelength for the electron accelerated by 1.0xx10^(4) volts?

Answer»

Solution :Step I.Calculation of the velocity of elctron
ENERGY (kinetic energy)of eectron`=1.0xx10^(4)`volts.
`=1.0xx10^(4)xx1.6xx10^(-19)J=1.6xx10^(-15)J`
`=1.6xx10^(-15)kgm^(2)s^(-2)`
or`(1)//(2) mv^(2)=1.6xx10^(-15)kgm^(2)s^(-2)`
or`v=9((2xx1.6xx10^(-15)kgm^(2)s^(-2))/(9.1xx10^(-31)kg))^(1//2)=5.93xx10^(7)MS^(-1)`
Step II. Calculation of WAVELENGTH of the electron
According to de Broglie equation,
`gamma=h/(mv),gamma=((6..626xx10^(-34)kgm^(2)s^(-1)))/((9.1xx10^(-31)kg)xx(5.93xx10^(7)ms^(-1)))=1.22xx10^(-11)m`


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