What is the weight of calcium carbonate required for the production of 1 L of carbon dioxide at 27^(@)C and 750 mm, by the action of dilute hydrochloric acid?

What is the weight of calcium carbonate required for the production of

1.	What is the weight of calcium carbonate required for the production of 1 L of carbon dioxide at 27^(@)C and 750 mm, by the action of dilute hydrochloric acid?
Answer» Solution :Givne conditions STP conditions `{:(P_(1)="750 mm",P_(2)="760 mm"),(T_(1)="300 K",T_(2)="273 K"),(V_(1)="1 Lit",V_(2)=?):}` From the equation of state, the unknown volume is obtained `V_(2)=(P_(1)V_(1))/(T_(1))xx(T_(2))/(P_(2))=(750xx1xx273)/(300xx760)=0.898L` Calcium carbonate on reaction with hydrochloric acid gives CARBONDIOXIDE. `CaCO_(3)+2HClrarrCaCl_(2)+H_(2)O+CO_(2)` `"1 mole of "CO_(2)-="1 mole of "CaCO_(3)` `"22.4L of "CO_(2)"at STP"="100 grams of "CaCO_(3)` `"0.898 L of "CO_(2)" at STP = ?"` The weight of calcium carbonate required = `(100xx0.989)/(*22.4)="4.009 grams"`