1.

What is the work done in blowing a soap bubble from a radius of 3 cm to 5cm ? Surface tension of the soap solution is 0.03Nm^(9-1).

Answer»

`0.2pimJ`
`2pimJ`
`0.4pimJ`
`4pimJ`

Solution :`W=2TxxDeltaA=2Txx(4piR_(2)^(2)-4piR_(1)^(2))`
(There are TWO free SURFACE of soap bubble)
`=8piTxx(R_(2)^(2)-R_(1)^(2))`
`=8xxpixx0.03[25xx10^(-4)-9xx10^(-4)]`
`=8xxpixx0.03xx16xx10^(-4)`
`=0.4pixx10^(-3)J`
`thereforeW=0.4pimJ`


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