1.

What is the work done in increasing the angular frequency of a circular ring of mass 2kg and radius 25 cm from 10 rpm to 20 rpm about ist axis?

Answer»

SOLUTION :WORK DONE = Increase in rotational kinetic
energy `=(1)/(2)l(omega_(f)^(2)-omega_(i)^(2))=(1)/(2)MR^(2)(omega_(f)^(2)-omega_(i)^(2))`
`=(1)/(2)xx2xx(0.25)^(2)(((2pi)/(3))^(2)-((pi)/(3))^(2))=0.2058J`


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