1.

What is the work done in taking an object of mass 1kg from the surface of the earth to a height equal to the radius of the earth ? ( G = 6.67 xx10^(-11) Nm^(2)//kg^(2)Radius of the earth = 6409km, Mass of the earth = 6 xx10^(24)kg)

Answer»

Solution :The work done in TAKING an OBJECT to a height
= `(GMm)/(R(R+h)), ""` Here h = R
`= (6.67 xx10^(-11) xx6 xx10^(24) xx1)/(2xx6.4 xx10^(24) xx1) = 3.127 xx10^(7)J`


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