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What is theheat of formation of C_(6)H_(6), given that the heats of combustion of benzene, carbon and hydrogen are 782, 94 and 68K. Cal respectively |
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Answer» `+14` KCAL `DELTA H_("comb") = 6 Delta H_(f_(CO_(2))) + 3 Delta H_(f_(H_(2)O)) - Delta H_(f_(C_(6)H_(6)))` `-782 = 6 XX (-94) + 3 xx (-68) - Delta H_(f_(C_(6)H_(6)))` `rArr Delta H_(f_(C_(6)H_(6))) = + 14` Kcal |
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