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What is theheat of formation of C_(6)H_(6), given that the heats of combustion of benzene, carbon and hydrogen are 782, 94 and 68K. Cal respectively

Answer»

`+14` KCAL
`-14` kCal
`+28` kCal
`-28` kCal

Solution :`C_(6)H_(6) + (15)/(2)O_(2) rarr 6CO_(2) + 3H_(2)O`
`DELTA H_("comb") = 6 Delta H_(f_(CO_(2))) + 3 Delta H_(f_(H_(2)O)) - Delta H_(f_(C_(6)H_(6)))`
`-782 = 6 XX (-94) + 3 xx (-68) - Delta H_(f_(C_(6)H_(6)))`
`rArr Delta H_(f_(C_(6)H_(6))) = + 14` Kcal


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