1.

What is thepH of the buffer solutioncontaining0.15 mol of NH_(4)OHand 0.25 mol of NH_(4)Cl ?K_(b)for NH_(4)OH is 1.98 xx10^(-5)

Answer»

10
9
`9.2`
`10.2`

SOLUTION :`14 - PH = pK_(b) + log. (["SALT"])/(["Base"])`
` - log (1.98 xx10^(-5))+ log. ((0.25)/(0.15))`
`pH = 9 `


Discussion

No Comment Found