1.

What is X, in the following reaction ? KHSO_(4) + F_(2) rarr HF + X

Answer»

`K_(2)SO_(4)`
`K_(2)S_(2)O_(4)`
`K_(2)S_(2)O_(3)`
`K_(2)S_(2)O_(8)`

Solution :`F_(2)` acts as an oxidising AGENT and HENCE converts `KHSO_(4)` to `K_(2)S_(2)O_(8)` (X).
`2KHSO_(4) + F_(2) rarr 2 HF + underset(X) (K_(2)S_(2)O_(8))`


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